Calculate The percent Water In CoC2H3O22 x 4H2O?

Answer 1

1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).

MM Co(C2H3O2)2: 177.02g (anhydrate)

+ MM 4H2O: 72.06g (water)

MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)

2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).

72.06g

249.08g x 100%

Percent water of hydrate is 28.93%.

Finding Molar Mass

# atoms Element A * Atomic Mass Element A = Mass A

# atoms Element B * Atomic Mass Element B = Mass B

... etc.

Add up all of the mass values and you have the molar mass of the substance.

Answer 2

To calculate the percent water in Co(C2H3O2)2 x 4H2O, first find the molar mass of Co(C2H3O2)2 x 4H2O: 58.93 (Co) + 2*(12.01 (C) + 1.01 (H) + 16.00 (O)) + 4*(18.02 (H2O)). The molar mass is 237.02 g/mol. Next, calculate the molar mass due to water: 4*(18.02) = 72.08 g/mol. The percent water is calculated by (molar mass of water in formula / molar mass of compound) x 100: (72.08 / 237.02) x 100 = 30.42%.