1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).
MM Co(C2H3O2)2: 177.02g (anhydrate)
+ MM 4H2O: 72.06g (water)
MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)
2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).
72.06g
249.08g x 100%
Percent water of hydrate is 28.93%.
Finding Molar Mass
# atoms Element A * Atomic Mass Element A = Mass A
# atoms Element B * Atomic Mass Element B = Mass B
... etc.
Add up all of the mass values and you have the molar mass of the substance.
To calculate the percent water in Co(C2H3O2)2 x 4H2O, first find the molar mass of Co(C2H3O2)2 x 4H2O: 58.93 (Co) + 2*(12.01 (C) + 1.01 (H) + 16.00 (O)) + 4*(18.02 (H2O)). The molar mass is 237.02 g/mol. Next, calculate the molar mass due to water: 4*(18.02) = 72.08 g/mol. The percent water is calculated by (molar mass of water in formula / molar mass of compound) x 100: (72.08 / 237.02) x 100 = 30.42%.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
The balanced equation is: C3H4O7 + 8O2 → 4H2O + 3CO2
Propane requires three molecules of oxygen to completely burn and produce carbon dioxide and water.
The chemical formula for nickel II sulfate hexahydrate is NiSO4•6H2O. It consists of one nickel (Ni) atom, one sulfur (S) atom, four oxygen (O) atoms, and six water (H2O) molecules.
Copper(II) chloride dihydrate
coefficiant
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
C3h8 + 5o2 -----> 3co2 + 4h2o
The formula 4H2O means there are 4 water molecules (H2O) present. Each water molecule consists of 2 hydrogen atoms and 1 oxygen atom. Therefore, in 4H2O there are 8 hydrogen atoms and 4 oxygen atoms in total.
It depends upon the extent of combustion take propane as an example Complete Combustion: C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l) Incomplete Combustion: C3H8(g) + 3.5O2(g) --> 3CO(g) + 4H2O(l) Very Incomplete Combustion: C3H8(g) + 2O2(g) --> 3C(s) + 4H2O(l) Products of Complete = Carbon Dioxide + Water Products of Incomplete = Carbon Monoxide + Water Products of Very Incomplete = Amorphous Carbon (soot) + Water
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
2NH4NO3->2N2+O2+4H2O
The coefficient for H2O in an equation represents the number of water molecules. In this case, the coefficient for 4H2O would mean there are 4 water molecules present.
2ch4 + 3o2 ==> 2c2o + 4h2o
it is combustion reaction, thus will produce water and carbon dioxide. C3H8 + 5O2 --> 3CO2 +4H2O
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O