1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).
MM Co(C2H3O2)2: 177.02g (anhydrate)
+ MM 4H2O: 72.06g (water)
MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)
2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).
72.06g
249.08g x 100%
Percent water of hydrate is 28.93%.
Finding Molar Mass
# atoms Element A * Atomic Mass Element A = Mass A
# atoms Element B * Atomic Mass Element B = Mass B
... etc.
Add up all of the mass values and you have the molar mass of the substance.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
The balanced equation is: C3H4O7 + 8O2 → 4H2O + 3CO2
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
The formula for nickel II sulfate tetrahydrate is NiSO4 * 4H2O.
hydrochloric acid
coefficiant
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
C3h8 + 5o2 -----> 3co2 + 4h2o
The "4" means that there are 4 water (H2O) molecules. The subscript of 2 on hydrogen means that there are two Hydrogens per molecule of water, so there are 8 hydrogens and 4 oxygens in all, since Oxygen has a subscript of 1.
It depends upon the extent of combustion take propane as an example Complete Combustion: C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l) Incomplete Combustion: C3H8(g) + 3.5O2(g) --> 3CO(g) + 4H2O(l) Very Incomplete Combustion: C3H8(g) + 2O2(g) --> 3C(s) + 4H2O(l) Products of Complete = Carbon Dioxide + Water Products of Incomplete = Carbon Monoxide + Water Products of Very Incomplete = Amorphous Carbon (soot) + Water
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
2NH4NO3->2N2+O2+4H2O
The coefficient for H2O in an equation represents the number of water molecules. In this case, the coefficient for 4H2O would mean there are 4 water molecules present.
it is combustion reaction, thus will produce water and carbon dioxide. C3H8 + 5O2 --> 3CO2 +4H2O
2ch4 + 3o2 ==> 2c2o + 4h2o
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O