1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).
MM Co(C2H3O2)2: 177.02g (anhydrate)
+ MM 4H2O: 72.06g (water)
MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)
2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).
72.06g
249.08g x 100%
Percent water of hydrate is 28.93%.
Finding Molar Mass
# atoms Element A * Atomic Mass Element A = Mass A
# atoms Element B * Atomic Mass Element B = Mass B
... etc.
Add up all of the mass values and you have the molar mass of the substance.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
No, the equation 2CH4 + 4O2 → 2CO2 + 4H2O is not balanced as written. The correct balanced equation should be 2CH4 + 3O2 → 2CO2 + 4H2O, which shows that two molecules of methane (CH4) react with three molecules of oxygen (O2) to produce two molecules of carbon dioxide (CO2) and four molecules of water (H2O). Balancing chemical equations ensures that the number of atoms for each element is the same on both sides of the equation.
The balanced equation is: C3H4O7 + 8O2 → 4H2O + 3CO2
In the chemical formula for water, H₂O, each molecule contains two hydrogen atoms. Therefore, in 4 molecules of water (4H₂O), there are a total of 4 × 2 = 8 hydrogen atoms.
The reaction between 3Fe and 4H2O to form Fe3O4 and 4H2 is a reduction-oxidation (redox) reaction. In this process, iron (Fe) is oxidized to form Fe3O4, while water (H2O) is reduced to produce hydrogen gas (H2). The transfer of electrons between the reactants characterizes this type of reaction.
coefficiant
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
C3h8 + 5o2 -----> 3co2 + 4h2o
The "4" means that there are 4 water (H2O) molecules. The subscript of 2 on hydrogen means that there are two Hydrogens per molecule of water, so there are 8 hydrogens and 4 oxygens in all, since Oxygen has a subscript of 1.
It depends upon the extent of combustion take propane as an example Complete Combustion: C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l) Incomplete Combustion: C3H8(g) + 3.5O2(g) --> 3CO(g) + 4H2O(l) Very Incomplete Combustion: C3H8(g) + 2O2(g) --> 3C(s) + 4H2O(l) Products of Complete = Carbon Dioxide + Water Products of Incomplete = Carbon Monoxide + Water Products of Very Incomplete = Amorphous Carbon (soot) + Water
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
2NH4NO3->2N2+O2+4H2O
The coefficient for H2O in an equation represents the number of water molecules. In this case, the coefficient for 4H2O would mean there are 4 water molecules present.
it is combustion reaction, thus will produce water and carbon dioxide. C3H8 + 5O2 --> 3CO2 +4H2O
2ch4 + 3o2 ==> 2c2o + 4h2o
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O