1000 amps
i think you mean meters and if that's right there is about 3 feet in 1 meeter :Di think you mean meters and if that's right there is about 3 feet in 1 meeter :D
The change in potential energy is equal to mass*gravity*change in height
70 feet = 21.336 meters.
Current flow can be calculated using Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R), represented by the formula I = V/R. By measuring the voltage across a circuit and knowing the resistance, you can calculate the current flowing through it.
Kirchhoff's Current Law (KCL) states that the total current entering a junction in a circuit must equal the total current leaving the junction. Kirchhoff's Voltage Law (KVL) states that the sum of the voltage drops across all elements in a closed loop in a circuit is equal to the applied voltage in that loop.
The resistance R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A)
In a simple circuit, the amount of voltage, and the resistance of the load. Amps = volts / ohms. For a motor, the back EMF when the rotor is turning reduces the effective voltage across the windings, reducing the current. That is why a motor may burn out if it is powered but cannot turn.
Amps are only a measure of electric current and not energy. The energy is equal to the power times the time, and the power is equal to the volts times the amps. So to find out the cost, you need the voltage, the current and the time.As an example 240 volts at 10 amps is 2.4 kW, and when run for one hour that uses 2.4 kWh (or Units) of energy.
It is equal to 1/2 MV2, M=mass, V=velocity
The number of amps cannot be determined from just the energy in joules. To calculate the current in amps, you would need to know the voltage of the circuit as well. Amps is equal to power (in watts) divided by voltage.
Current stops going into a capacitor when it's voltage is equal to the supply voltage. From then there is no flow of current, so there is no magnetic field. Yet the capacitor remains charged and has energy to release if required.
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.