1. Find volume of spheres = 4/3pr3 and multiply by 4 since there are 4 spheres.
2. Find volume of units cell = l 3 = (2Ö2r)3.
3. Find volume of empty space = vol unit cell minus volume of spheres.
4. Divide volume empty space by volume of unit cell.
It works out to 25.952
4 significant figures.
There are 3 significant figures in 94.2.
Trailing zeros ALWAYS count as significant figures, so 700.0 would have 4 significant figures.
There are 4 of them
5 significant figures
Count the significant figures in each number. Calculate the minimum of these numbers. Do the multiplication Round the product to the LEAST number of significant figures, determined above.
4 significant figures.
Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.
There are 3 significant figures in 94.2.
There are 4 significant figures in 0.0032. Seems to be only 2 significant figures in this number.
There are four significant figures in 0.1111.
20.2 has three significant figures.
Trailing zeros ALWAYS count as significant figures, so 700.0 would have 4 significant figures.
There are two significant figures in 0.025.
5 significant figures.
145.75+2.3*10^-1 145.75+0.23 145.98 As 2.3*10^-1 has two significant figures, our answer must have two significant figures 145.98 150 As the 5.98 rounds up to the nearest significant figure 1.5*10^2
That depends on how many significant figures you are talking about.If three significant figures then 700 is the largest that rounds to 700.If four significant figures are to be rounded to three significant figures then 700.4If five significant figures are to be rounded to three significant figures then 700.49If six significant figures are to be rounded to three significant figures then 700.499etc.