briefly discuss the errors tahat occur in the above titration and the change in the colour of the indicators.
10kg of water contains 10l of water. So morality is 0.2mildm-3.
40 metric cups is 10L
10
5240mL = 5.24L fraction: = 5.24L/10L * 100/100 = 524/1000
Assuming that gas being used is an ideal gas, the gas law equation PV=nRT can be used. P=Pressure (atm) V=Volume (Liters) n=Moles R=0.08206 (a gas constant) T=Temperature (Kelvin) In this problem we know that there is a 10L container with 3.84atm of pressure at 35 C. So P=3.84atm, V=10L, and R=0.08206. To calculate T, you need to convert from Celsius (C) to Kelvin (K). Using the formula K=273+C, you should get T=308K. Now you know all of the variables you can work the problem out. Solve the equation for moles(n) by dividing each side by R and T: (PV/RT)=n Plug in your numbers and solve with a calculator: n=(3.84)(10)/(0.08206)(308) =(38.4)/(25.27448) =1.5193190918 Leaving us a rounded answer of 1.52n in the container
Molarity=moles of solute/liters of solvent=5mol/10L=0.5M
10,000 mL = 10L
10kg of water contains 10l of water. So morality is 0.2mildm-3.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
10l 9l = 9l 870ml - 0.87l 9l + 0.87l = 9.87l 9.87l to the nearest whole litre is 10l (because 9.87l is closer to 10l than it is to 9l)
You can safely put 2ml into the 10l aquarium
10
10L
10 Liters
1000cL equals 10L* There are 100cL per liter
10L = 1000cl
The volume of a car tire is about 10L.