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Calculate the time required to dial the number 009144414630 using a rotary dial telephone if subscriber takes 600ms on an average to rotate the dial for a single digit and interdigit gap is 200ms.?
Wiki User
∙ 14y ago
if you add 600ms+200ms =800ms each number x 12 =9.6 seconds
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I disagree. The answer is the sum of the time that takes in the total dialing spaces. So, in 0 there are 10 spaces; in 9 - are 9, etc.(10 + 10 + 9 + 1 + 4 + 4 + 4 + 1 + 4 + 6 + 3 + 10 ) x 600 ms = 13200ms = 13.2 seconds.[??? 66 x 600 = 39600ms = 39.6 seconds]
AnswerFor every digit for ex. 009144414630 the ave. single digit is 600 msso we count the no. of digits of the telephone number.. in this example the total # of digits is 12. Use the formula:
Time= [(n x T) + ((n-1)x t)]
where: n= no. of digits
T= single digit time
t= interdigit gap time
if you want to know its 9400ms or 94 sec
[??? 9400 ms = 9.4 seconds]
Alternative:
I would take the problem to mean:
Once the dialer has chosen the digit to be dialed and has dialed it (cocked it), the mechanism requires 600 ms per increment to actually register the digit and return to the ready state to accept another digit. That is to say; it takes the dialer 200 ms to chose and "cock" a specific digit into the rotor and 600 ms per increment for the rotor to "count it off", returning to the ready state. A "1" takes 600 ms to register, "2" takes 1200 ms and so on to the "0" which takes 6000 ms to complete.
(6000 ms = 6 seconds and I am sure that the old rotary phones were not that slow. Therefore, I suspect that the author added a zero and the 600 ms is really only 60 ms which gives a time of 0.6 seconds for the "0" to complete. However, by the same token, 200 ms or 1/5-second does not seem to be excessive for choosing and "cocking" a digit so I will stick with that figure in the following.)
From the word "Go", the dialer must chose and cock each digit of the number to be dialed.
# of digits to be dialed = 12
Dialer time = 12 x 200 ms = 2400 ms
# of dialing increments = 10+10+9+1+4+4+4+1+4+3+6+10 = 66
Rotor time = 66 x 60 ms = 3960 ms (39600 ms @ 600 ms)
Total time = 6360 ms = 6.36 seconds (42 seconds @ 600 ms)
This question has created a mess. Other sources put the pulse rate of rotary phones @ 10 pps to 20 pps and that would seem to indicate 1 to 0.5 seconds to tap out 10 pulses, a far cry from the 6 seconds indicated by the 600 ms rate given in the original question.
Buddika:
I think it should be in following way
step 1: Average time to dial 12 digits 12 * 600ms=7.2 s
step 2: if pulse rate is 10 pulse/sec and 10% tolerance
pulse time=(10+10+9+1+4+4+4+1+4+6+3+10)/10
= 6.6s
tolerance = +_6.6 10%=+_0.66s
Mean tolerance=0.66/2=0.33s
Total pulse time=6.93s
step 3: Total inter-digit gap=11*200ms=2.2s
So total time=7.2+6.93+2.2=16.33s(but book says its 16.44s)
Wiki User
∙ 14y ago
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