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Can -49 be a probability

Updated: 8/18/2019
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13y ago

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No it can not; probability must be between 0 and 1, inclusive.

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13y ago
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Q: Can -49 be a probability
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Related questions

What is the probability to choose a prime number from 1 to 49?

15 from 49


What is the probability of a prime number being picked randomly from the numbers 1 through 49?

There are 15 primes from 1 to 49 (including '1').The probability is (15/49) = 30.612 %(rounded)


What is the probability of a prime number being picked randomly from the numbers 1 -49?

The probability of a prime number in a random pick from the numbers 1-49 is 15 in 49, as there are 15 prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43,and 47) in the range of 1 to 49.


What cannot be a probability 0 -49 0.001 14 percent?

Probabilities can only range from 0 to 1. All of the options range from 0 to 1 (14% is the same as 0.14) except -49, so -49 is not a probability.


What is the probability of a prime number being picked randomly from the number 49?

Since 49 is a composite, the answer is 0.


What is the probability a student can answer 49 out of 50 questions wrong on a four answer multiple choice exam?

Assuming the questions are answered at random, the probability is 0.000009, approx.


How do you measure probability?

You collect data. Flip a coin 100 times, you get 49 heads and 51 tails, so the probability of H is 0.49.


What is the probability that a 70 percent free throw shooter would make 1 of 2 shots?

The probability the shooter makes both shots is .7 * .7 = .49, and the probability of making neither is .3 * .3 = .09. So the probability of making exactly 1 out of 2 is 1 - .49 - .9 = .42, or 42 percent.


What is the probability of prime numbers being chosen randomly from the number 1-49?

15/49ExplanationThere are 15 prime numbers between 1 and 49 (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47). If you randomly choose one natural number from the 49 numbers between 1 and 49 inclusive, there is a 15/49 probability that it will be prime.


If A box contains three black balls and four gold balls Two balls are randomly drawn in succession from the box If there is no replacement what is the probability that both balls are black?

(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.


If a 4 digit number is chosen at random what is the probability that the product of the digits is 12?

49/9000


Is negative 49 a probability?

No, it's not a probability since it's not set in terms of ratio of two values, such that the second value is greater than the first. For instance: 1 to 2 or 1 / 2. Also, probability is never negative.