No because it will have a remainder of 1
If the sum of the digits equals 3, the number is evenly divisible by 3. 2 + 0 + 1 = 3, so 201 is evenly divisible by 3. 1, 3, 67, 201
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
Yes, but not evenly.
No, 3 cannot go into 49 evenly because 49 is not divisible by 3 without leaving a remainder.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
only 1 and 7 can go into 7 evenly.. but 9 and 3 go into 27 evenly
Add the number's digits. If the sum is evenly divisible by 3, then so is the number. So, will 3 divide evenly into 2,169,252? Yes it will, because the sum of the digits is 27, and 27 is divisble by 3. If you want, you can keep adding numbers until one digit remains. For example, keep going with 27. 2 + 7 = 9, which is also evenly divisible by 3.
Not evenly.
No
Not evenly.
No.