Yes, it should function. the only problem being the power output which will be slightly less or the consumption greater. The only possible problem being if it is an electronicly controlled one, then a "guard dog" system may stop the heater from working. Guard dog is a system which stops systems from operating at a too low voltage as this may cause regulation problems .
Power= voltage X currant so for the same power output the heater will have to consume more amps (or the power will diminish in proportion to the voltage drop).
CCVIII C = 100 V= 5 III = 3
D=M/V D=240/200 D=1.2 you should include units though. I'm not sure what units you used, which is why i didn't write them.
You mean the formula v = u + at, where v is final velocity, u is starting velocity, a is the rate of acceleration and t is the time taken. Well if a car's acceleration is 20 feet per second per second, in 12 seconds its velocity will have been increased to 20 x 12 = 240 feet per second. So if before it accelerated it was travelling at 100 feet per second, its new speed will be 240 + 100 = 340 feet per second = 340 x 60 x 60 ft per hour = 1224000 ft/hr which is just under 219 mph! Some car!
On a car it is the tube that takes a v-8's 2 exhaust headers and combines them into a a single exhaust to run thru 1 muffler.
To find the average speed you must know the total distance traveled and the total elapsed. The distance traveled in each interval is simply the speed multiplied by the time (v x t). Thus, in the first interval you travel 120 x 1 = 120 meters, in the second interval 120 x 6 = 720 meters; therefore, the total distance traveled is 840 meters. The total time elapsed is 120 + 120 = 240 seconds. An average speed is simply the total distance traveled divided by the total time elapsed thus in this case it is 720 m / 240 s = 3 m/s.
This is not recommended. The heater will operate at more than its given specified wattage. A 208 volt heater run off 220 volts will have an output increase by 11.87 percent. Similarly, a 220 volt heater can be run off of 208 but the wattage will be reduced by 10.61%. The calculations, using Ohms' Law, are shown below.Watts = volts x amps (W = V x I) and I = W / V so, if we take a 2000 watts heater designed to run on 208 volts, I = 2000 / 208 = 9.6 ampsResistance = volts / amps (R = V / I) so the heater's resistance is 208 / 9.6 = 21.632 ohmsAmps = volts / resistance (I = V / R) so, running on 220 volts, I = 220 / 21.632 = 10.17 ampsW = 220 x 10.17 = 2237 watts, which is an increase of 2237/2000 = 11.87%.W = V x I and I = W / V so, if we take a 2000 watts heater designed to run on 220 volts, I = 2000 / 220 = 9.09 ampsR = V / I so the heater's resistance is 220 / 9.09 = 24.2 ohmsI = V / R so, running on 208 volts, I = 208 / 24.2 = 8.595 ampsW = 208 x 8.595 = 1787.76 watts, which is a decrease of ( 2000-1787.76 ) / 2000 = 10.61%.
Yes but a 208 volt heater is intended to be delta connected so there are only three terminals. The three heating elements could be rewired to run in parallel off a 220 v single phase circuit, and the heater would then operate at 12% excessive power, which might shorten its life. <<>> No. The heater will operate over its given specified wattage. A 208 volt heater run off of 240 volt will have an output increase. Ohms law stated that current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. A 240 volt heater can be run off of 208 but the wattage will be reduced. For example if the heater is 5000 watts at 208 volts, the current is I =W/E 5000/208 = 24 amps. The resistance of the heater is R = W/I (squared) =5000/24 x 24 (576) = 8.68 ohms. Applying 240 volts on the same heater whose resistance is 8.68 ohms results in this new heater wattage rating. W = E (squared)/R = 240 x 240 (57600)/8.68 = 6636 watts. This is 1636 watts higher than the manufacturer's safety rating. W = watts, I = amperage, R= resistance in ohms and E = voltage.
No, not really. The two hot legs can be opposite legs of a 120/240 V split phase power source. You still do need a protective earth ground, however, but the heater itself does not require a grounded neutral to run.
yes and and no but you need to know how many amps the heater uses and how many amps the relay can with stand..
Yes if it is connected across the lines it will receive 208 volts, which is obviously less than 240 v and the power output would be only three quarters of the rated power.
If you have the right materials than yes it is possible, but i would highly recommend that you protect yourself.
If you have the right materials than yes it is possible, but i would highly recommend that you protect yourself.
12 amps
The drier should have its operating voltage range marked on it. A heating element designed for 240 v would use 25% less electric power and produce 25% less heat when run on 208 v. So it would still dry clothes but it would take longer. If it has a motor to rotate it, whether the motor would operate correctly on 208 v is another matter.
VOLTS x (VOLTS/OHMS) = WATTS 240 X (240/8) = 7200 Watts = 7.2KWatts
A 208 v three-phase system has 120 v between each live wire and the neutral. It is used in the USA as an alternative to the 120/240 v single-phase system, offering 50% more power for the same current.
If it is a 240 v delta motor it needs a 240 v three-phase supply, which has 139 v between line and neutral, so 440 v would not be acceptable.