0
Add your answer:
Earn +20 pts
When the cardboard is at rest how do the magnitudes and directions of the pair of forces acting on it?
answer
When the cardboard is at rest how do the magnitudes and directions of the pair forces acting on it compare?
answer
When the cardboard is at rest how do the magnitudes and directions of the pair of forces acting on it compare?
answer
What shape has a pair of unequal parallel sides?
trapezium :)
For any triangle made of vectors will any pair of vectors that form its sides be equal vectors?
No. Only in the equilateral case. And then they will only be equal in magnitude, not direction.
What is a polar molecue?
its the result of unequal sharing of a pair of electrons
WHEN THE CARDBOARD IS AT RESThow do the magnitudes and directions of the pair of forces acting on it compare?
When the cardboard is at rest, the magnitudes of the pair of forces acting on it are equal. These forces form an action-reaction pair, with one force pushing or pulling in one direction, and the other force of equal magnitude pushing or pulling in the opposite direction.
What is non-coplaner vectors?
They are a pair of vectors which are not parallel but whose lines of action cannot meet.
What is the magnitude of the resultant of a pair of perpendicular 300 N vectors?
The magnitude depends on the angle between the vectors. The magnitude could be from 0 to 600 N.
When an object is at rest how the magnitudes and directions of the pair of forces acting on it compare?
When an object is at rest, the magnitudes of the pair of forces acting on it are equal but opposite in direction. This is in line with Newton's first law of motion, which states that an object at rest will remain at rest unless acted upon by an external force.
When the cardboard is at rest how do magnitudes and directions of the pair of forces acting on it?
answer
What is my result if i calculate the magnitude of the resultant of a pair of 84 km h velocity vectors that are at right angles to each other?
If two vectors with equal magnitudes 'M' have perpendicular directions, then the resultant ismidway between them ... 45 degrees from each ... and the magnitude of the resultant isM sqrt(2).84 km/hr North + 84 km/hr East = 84 sqrt(2) = 118.794 km/hr Northeast (rounded).
