Under normal scenarios, a polygon cannot have exactly 10 diagonals
38 diagonals
Such a polygon does not exist. A polygon with n sides has 0.5*n*(n-3) diagonals If there are 10 diagonals then 0.5*n*(n-3) = 10 which requires n2 - 3n - 20 = 0 which has no integer roots.
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.
None because it does not comply with the formula 0.5*(n2-3n) = diagonals
A polygon that has 104 diagonals will have 16 sides
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
That polygon is called a "triangle". It has no diagonals.
An 11 sided polygon has 44 diagonals.
There are 90 diagonals in a 15-sided polygon.
A four-sided polygon has two diagonals.
No