Yes.
Lateral faces are the number of faces excluding the base. Since the square is the base, the other 4 sides will each be touching a lateral face to form a square pyramid (or it wont be a pyramid). So, there are 4.
LA = 1/2psnewtest3
A pyramid
Five, counting the square base.
Five, counting the square base.
One side will be a square. It is the base. The lateral sides are triangles.
A regular pyramid is a right pyramid whose base is a regular polygon. There are only three regular pyramids: a regular tetrahedron, a regular square pyramid, and a regular pentagonal pyramid.
The lateral surface area of a square pyramid can be calculated using the formula: ( \text{Lateral Area} = 2 \times \text{base length} \times \text{slant height} ). Here, the base length refers to the length of one side of the square base, and the slant height is the height of the triangular face from the base to the apex of the pyramid. To find the total lateral area, simply plug in the values for the base length and slant height into the formula.
I doubt it because no matter how big the base is, if you laid the triangles in to the position of the base (ex 4 triangles to a square base) they would have a larger area than the base shape
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm is: 64 cm3
To find the lateral height of a square pyramid, first identify the apex (top point) of the pyramid and the midpoint of one of its base sides. The lateral height is the length of the segment connecting the apex to this midpoint. You can use the Pythagorean theorem, where the lateral height forms the hypotenuse of a right triangle with the height of the pyramid and half the base length as the two other sides. Thus, the formula is ( l = \sqrt{h^2 + \left(\frac{b}{2}\right)^2} ), where ( l ) is the lateral height, ( h ) is the height, and ( b ) is the length of a base side.
72 cm square.