A vector comprises its components, which are orthogonal. If just one of them has magnitude and direction, then the resultant vector has magnitude and direction. Example:- If A is a vector and Ax is zero and Ay is non-zero then, A=Ax+Ay A=0+Ay A=Ay
If all the components of a vector are zero, the magnitude of the vector will always be zero.
Yes. For instance, the 2-dimensional vector (1,0) has length sqrt(1+0) = 1 A vector only has zero magnitude when all its components are 0.
Yes. A vector in two dimensions is broken into two components, a vector in three dimensions broken into three components, etc... If the value of all but one component of a vector equal zero then the magnitude of the vector is equal to the non-zero component.
The magnitude of the zero vector is zero, hence the name.
No, Magnitude is computed using the sum of squares of the components. Since squares are never negative, if one component is non-zero the result is necessarily positive.ANS2:Sum of the squares?! Somebody has been smoking something. If the magnitude is zero, that means that the components' sums are zero. That condition is called dynamic equilibrium. An apple on a table is experiencing a downward force from gravity and an upward force from the table. They add to zero and the apple just sits there. The downward force of gravity is -9.81 m/s^2 x the mass of the apple. The components acting on the apple are equal in magnitude but opposite in direction.
If all the components of a vector are zero, the magnitude of the vector will always be zero.
Yes. For instance, the 2-dimensional vector (1,0) has length sqrt(1+0) = 1 A vector only has zero magnitude when all its components are 0.
No. In order for the magnitude of a vector to be zero, the magnitude of all of its components will need to be zero.This answer ignores velocity and considers only the various N-axis projections of a vector. This is because direction is moot if magnitude is zero.
Yes. A vector in two dimensions is broken into two components, a vector in three dimensions broken into three components, etc... If the value of all but one component of a vector equal zero then the magnitude of the vector is equal to the non-zero component.
The magnitude of the zero vector is zero, hence the name.
NO, a vector will not be zero if one of its components will be zero.
When the direction of the vector is vertical. Gravitational force has zero horizontal component.
No. The magnitude of a vector can't be less than any component.
No, Magnitude is computed using the sum of squares of the components. Since squares are never negative, if one component is non-zero the result is necessarily positive.ANS2:Sum of the squares?! Somebody has been smoking something. If the magnitude is zero, that means that the components' sums are zero. That condition is called dynamic equilibrium. An apple on a table is experiencing a downward force from gravity and an upward force from the table. They add to zero and the apple just sits there. The downward force of gravity is -9.81 m/s^2 x the mass of the apple. The components acting on the apple are equal in magnitude but opposite in direction.
All components of the zero vector equal to zero.
Yes. - if all the other components are zero. When the word "component" means the mutually perpendicular vectors that add (through vector addition) to form the resultant, then then answer is that "the magnitude of a vector" can equal one of its components, if and only if all other components have zero length (magnitude). This answer applies to the typical case of a vector being expressed in terms of components defined by an orthogonal basis. In normal space, these basis vectors merely define the relevant orthogonal coordinate system. There are, however, mathematical systems that use a nonorthogonal basis and the answer is different and presumably not part of the submitted question.
No.