get a cut out shape of octagon, then get cut out triangles and try to fit in the triangles covering all the octagon but here is the solution... j
Regular polygons: Equilateral triangles, squares, rectangles, rhombi, hexagons. Irregular polygons: Isosceles triangles and symmetric trapeziums (isosceles triangles with the odd angle cut off by a line parallel to the base) will do if they are alternating up and down. There are also many irregular shapes. MC Escher (see for example, http:/www.mcescher.com/Gallery/gallery-symmetry.htm) used repeated irregular shapes to tessellate. Although some of these have curved sides, they can be replaced by appropriate straight sides to produce polygons which will do the trick.
it's impossible to have a quadrilateral that can't be cut into triangles.
Cut it just like a pizza. Cut it from the middle top to the middle bottom and from the middle left side to the middle right side. You should have four smaller squares all of equal size. Now cut each square diagonally to make 8 triangles. All 8 triangles are the same size. -- Place two diagonals from corner to corner or the square -- this is basically slicing the square into four, equal triangular quadrants. Then slice each of those triangles in half. That makes 8 triangles of equal area.
no its an emphatic statement all squares can be cut in half to make 2 congruent isosceles right triangles is perhaps as general a statement as is possible
cut it down the middle
It is 8 triangles
No. It is just the person preference.
For example an irregular and a regular octagon are alike because:- They both have 8 sides They both have 8 exterior angles that add up to 380 degrees They both have 8 interior angles that add up to 1080 degrees They both have 20 diagonals They both can be cut into 6 triangles
You can get 2 triangles by cutting a parallelogram in half
Princess cut diamonds
Cut each square diagonally to give two pairs of right angled triangles. Place all four triangles with their right angles around a point, their hypotenuses will form the sides of the single square.