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As an equation, x/x = x2, or x2 = x/x. Multiplying both sides by x: x3 = x. Put everything on the left side: x3 - x = 0. Factoring the left part: x(x2 - 1) = 0, or x(x+1)(x-1) = 0. This has the solutions 0, 1, -1. However, 0 doesn't make sense in the original equation - it seems that multiplying with "x" introduced an extra solution.

The remaining solutions, 1 and -1, fit the original specification.

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Q: Can any number divided by itself equal to the square of the original number?
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What do squares of numbers mean?

Square is a number multiplied by itself (ie. 7x7), while a square root is a number which can be divided so that the quotient multiplied by itself will equal that original number (ie. (36 divided by 6)x6=36.

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It is the square of the original number. If the original number represents a length, then the square of the original number represents an area of a square with side equal to the original number.

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You have squared the original number. The original number is now the square of the new quotient.

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1, any number that is divided by itself always equals 1

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To get the original number, multiply the square root of the number by itself.

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An even number is any integer that can be divided by two evenly. A square number is any integer multiplied by itself. 2 is even 3 is odd 4 is even and a square of 2 9 is odd and a square of 3 The square of any even number will itself be an even number, and the square of any odd number will itself be an odd number.

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