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8 / (√6 - √3)

= 8(√6 + √3) / (√6 - √3)(√6 + √3)

= 8(√6 + √3) / (6 - 3)

= 8√3(√2 + 1) / 3

If you don't need to keep it in proper form, you could divide both the numerator and denominator by √3:

= 8(√2 + 1) / √3

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13y ago

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