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Graph both, find intersects

x**2-y-4x+2=0 --> x**2-4x+2=y

x-2y+4=0 --> (x+4)/2=y

x**2-4x+2=(x+4)/2

2x**2-8x+4=x+4

2x**2-9x+4=4

2x**2-9x=0

x(2x-9)=0

x=0, 9/2

y=(0+4)/2=2

y=(9/2+4)/2=17/4

y=2, 17/4

Intersect coordinates

(0, 2), (4.5,4.25)

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Q: Can anyone solve x2-y-4x plus 2 equals 0 and x-2y plus 4 equals 0 using a graphing calculator?
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