No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A.
Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A.
An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)
No. An absolute value will always be positive, as it is a measurement of distance from zero on a number line.* * * * *Pedantically, not quite! It will always be non-negative: it can be 0.
13
13
Yes, if you are averaging numbers that include negative numbers.
The absolute value is the distance form zero. It is always positive.
see speed cannot de negative se speed = distance / time and neithr distance nor time can be negative they r always positive so speed cannot be negative but velocity can be negative
No. An absolute value will always be positive, as it is a measurement of distance from zero on a number line.* * * * *Pedantically, not quite! It will always be non-negative: it can be 0.
No, think of absolute value as distance and you can't have a negative distance.
yes it can be negative.
NO
No, it is not possible to have a negative solution when using the distance formula. Even if you were to go backwards, the distance would still be a positive number.
Yes it can. If distance and displacement is positive then it means it's going forwards. If you get a distance or displacement that is negative then means it's going the other direction, backwards.
The position of zero force if positive and negative charges are separated by a distance would be at half of the separation distance.
No. That would require a negative mass or a negative distance, neither of which is possible.
It is: (-2--2)2+(3--7)2 = 100 and the sq rt of this is the distance which is 10 units.
-5?
Negative