No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A.
Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A.
An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)
No. An absolute value will always be positive, as it is a measurement of distance from zero on a number line.* * * * *Pedantically, not quite! It will always be non-negative: it can be 0.
Yes, if you are averaging numbers that include negative numbers.
13
13
Yes.
No. An absolute value will always be positive, as it is a measurement of distance from zero on a number line.* * * * *Pedantically, not quite! It will always be non-negative: it can be 0.
No, think of absolute value as distance and you can't have a negative distance.
Yes it can. If distance and displacement is positive then it means it's going forwards. If you get a distance or displacement that is negative then means it's going the other direction, backwards.
see speed cannot de negative se speed = distance / time and neithr distance nor time can be negative they r always positive so speed cannot be negative but velocity can be negative
yes it can be negative.
No, it is not possible to have a negative solution when using the distance formula. Even if you were to go backwards, the distance would still be a positive number.
The position of zero force if positive and negative charges are separated by a distance would be at half of the separation distance.
It is: (-2--2)2+(3--7)2 = 100 and the sq rt of this is the distance which is 10 units.
Yes, if you are averaging numbers that include negative numbers.
-5?
Negative
13