Can someone explain the procedures for solving the following algebra 2 inverse functions y equals negative square root of 6x plus 3 y equals negative 3rd root of 8x plus 5?

Answer 1

I'm going to answer it.

y=-sqrt6x+3, y=-3rt8x+5

y=(-sqrt6x^2)+3, y=(-3rt8x^3)+5

y=-6x+3, y=-8x+5

Let's add them.

2y=-14x+8

Let's say y=0.

2(0)=-14x+8

0=-14x+8

Now we can solve for x.

-14x+8=0

-14x+8-8=0-8

-14x=-8

-14x/-14=-8/-14

x=4/7

Time to see if this is right.

0=-sqrt6(4/7)+3

0=-3rt8(4/7)+5

Time to fix this.

0=(-sqrt6(4/7)^2)+3

0=(-3rt8(4/7)^3)+5

That leaves you with these two equations.

0=-6(4/7)+3

0=-8(4/7)+5

Let's combine these two.

0=-14(4/7)+8

0=-8+8

0=0

Therefore,x=4/7, and y=0.