No.
Yes, the magnitude of the difference between two vectors can be greater than the magnitude of either vector. This can occur when the vectors are in opposite directions or have different magnitudes such that the resulting difference vector is longer than either of the original vectors.
yes,if the components are making angle 0<=theta<=90 no ,the magnitude of vector can never attain a negative value |a|=square root of both components which always gives a positive value
Yes. For example, if one vector has a length of 1 and points north, and the second vector has a length of 1 and points south, the difference (vector1 minus vector2) will have a length of 2 and point north.
Yes. - if all the other components are zero. When the word "component" means the mutually perpendicular vectors that add (through vector addition) to form the resultant, then then answer is that "the magnitude of a vector" can equal one of its components, if and only if all other components have zero length (magnitude). This answer applies to the typical case of a vector being expressed in terms of components defined by an orthogonal basis. In normal space, these basis vectors merely define the relevant orthogonal coordinate system. There are, however, mathematical systems that use a nonorthogonal basis and the answer is different and presumably not part of the submitted question.
Alaska has experienced several major earthquakes with a magnitude of 7.0 or greater in the last 200 years. Notably, the 1964 Alaska earthquake, also known as the Great Alaska earthquake, had a magnitude of 9.2 and is the second most powerful earthquake ever recorded.
Yes, if the two vectors are at a sufficiently large obtuse angle.The law of cosines gives the size of the resultant.If C = A + B, where A, B, C are vectors, then C is the "resultant."The law of cosines says, he magnitudes, A,B,C, are related as follows,C2=A2+B2+2AB cosine(theta),where theta is the angle between the vectors A and B. When theta is zero, then C has the maximum length, equal to the lengths of A and B added. When theta is 180 degrees, then C has the minimum length of the difference of the length of A and of B. Somewhere in between, the length of C will equal the length of the longer component and for larger angles be smaller.To be specific, suppose that A is the longer of the two, then the resultant, C, has the same length as A at one special angle which we will call theta*.A2=A2+B2+2AB cosine(theta*)cosine(theta*)=-B/(2A).The answer to the question is then, that for angles greater than theta* the resultant is smaller than the larger component. (Greater means, of course, greater than theta* and up to 360-theta*.)Note that if we ask whether the resultant can be smaller than the smaller of the two component vectors, then the answer is again yes and the above equation holds true when A is the smaller with the condition that it is not smaller than half the length of B. When the smaller vector is less than half the length of the larger component, then the resultant may equal the length of the larger but can never be made equal to the length of the smaller component.
9.5
The magnitude 9.5 earthquake that occurred in Valdivia Chile in 1960.
No there has never been an earthquake with a magnitude of 10.0 that has ever been recorded. The largest recorded to date was the magnitude 9.5 earthquake that occurred in Valdivia Chile in 1960.
Not really. The sum of the magnitudes is a scalar, not a vector - so they can't be equal. But the sum of the two vectors can have the same magnitude, if both vectors point in the same direction.
The strongest earthquake that can be measured using the Richter magnitude scale is one with a magnitude of 8.0. For earthquakes larger than this, the moment magnitude scale must be used.
The largest earthquakes ever was the Valdivia earthquake in Chile in 1960 with a magnitude of 9.5. The second largest was the Alaska earthquake in 1964 with a magnitude of 9.2.