Any two numbers of this type can be solved using boolean logics.......
It is very simple once had a glance on it .
Here is a method to prove x=y where x and y are any numbers.....
let XY = XY
We can rewrite the above as
ð X2 - (X+Y)*X = Y2 - (X+Y)*Y
ð Multiplying both sides with 2/2 we get
ð X2 - 2*x*(X+Y)/2 = Y2 - 2*Y*(X+Y)/2
ð Adding (X+Y)2/2 on both sides we get
ð X2 - 2*x*(X+Y)/2 + (X+Y)2/2= Y2 - 2*Y*(X+Y)/2 + (X+Y)2/2
ð This is in the form of a2-2ab +b2 = (a+b)2
ð (X - (X+Y)/2)2 = (Y-(X+Y)/2)2
ð Canceling the squares on both sides(case condition)
ð X-(X+Y)/2 = Y - (X+Y)/2
ð Canceling (X+Y)/2 on both sides
ð X=Y
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