Any two numbers of this type can be solved using boolean logics.......
It is very simple once had a glance on it .
Here is a method to prove x=y where x and y are any numbers.....
let XY = XY
We can rewrite the above as
ð X2 - (X+Y)*X = Y2 - (X+Y)*Y
ð Multiplying both sides with 2/2 we get
ð X2 - 2*x*(X+Y)/2 = Y2 - 2*Y*(X+Y)/2
ð Adding (X+Y)2/2 on both sides we get
ð X2 - 2*x*(X+Y)/2 + (X+Y)2/2= Y2 - 2*Y*(X+Y)/2 + (X+Y)2/2
ð This is in the form of a2-2ab +b2 = (a+b)2
ð (X - (X+Y)/2)2 = (Y-(X+Y)/2)2
ð Canceling the squares on both sides(case condition)
ð X-(X+Y)/2 = Y - (X+Y)/2
ð Canceling (X+Y)/2 on both sides
ð X=Y
You can't it equals 2. You can't it equals 2.
Using faulty logic.
1 is the answer. -(-4)- 3 = 4-3 = 1 .
4 plus 3 equals 7
3
To solve the equation "What times 4 equals 3," you would need to divide 3 by 4. The answer is 0.75. This is because 4 multiplied by 0.75 equals 3.
12 divided by 3 equals 4. Then, 4 times 3 equals 12. Finally, 4 plus 12 equals 16.
9
1
You cannot prove that sqrt(3)/2 = 0 because it is simply not true! The solution to the equation is theta (or, tita as you like to call it) = pi/6c or 30 degrees. The cosine of that angle is sqrt(3)/2 but that is NOT the same as it being 0.
3+4+6 easily equals 13. There is a few ways to do it. 3+4 equals seven. Then add 6 and you get 13. 3+6 equals nine. Then add 4 and you get 13. 4+6 equals ten. Then add 3 and you get 13.
No. It equals a quarter (1/4). But the quotient of 12 and 3 equals 4.