Yes I can.
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
The balanced equation for the reaction is: N2H4 + H2O2 -> N2 + H2O The coefficients for the balanced equation are: 1 N2H4 + 1 H2O2 -> 1 N2 + 2 H2O
n2 + 1 where n is an integer.
y = kn / (1 + n2)First, let's express it with negative exponents:y = kn * (1 + n2)-1Then apply the chain rule:dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2nAnd simplify:dy|dn = k / (1 + n2) - 2n / kn(1 + n2)
Not much more than any other series like this. If you stop at the nth position the sume so far is n2. Because (n+1)2 is n2 + (2n+1), and 2n+1 are the odd numbers.
n2 - 4 is the "difference of two squares." That factors to (n - 2)(n+2)a2 + 2a + 1 is "additive squares." That factors to (a + 1)(a + 1) or (a + 1)2
The formula for the sum of the series r(1/n2-1/n2) is r(1-1/n2).
(n2 + n)/2 1+2+3+4+5+n= 15+n
keq = 1.125
1+1+1+1=4
0 but if you add 1+1-1 it is 1
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.