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When we apply Euler's rule to polyedra, we generally term it the Euler characteristic. We'll find that every polyhedron will follow the rule. That rule is V - E + F= 2, where V = number of vertices, E = number of edges, and F = number of faces. The formula can appear in different forms, as you might guess, and just one is E + F - 2 = V. That said, no, it is not possible to construct a polyhedron that violates the Euler characteristic.
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What shape has 3 faces 9 edges and 6 vertices?
There is no simply connected polyhedron that meets these requirements because they do not satisfy the Euler characteristic.There is no simply connected polyhedron that meets these requirements because they do not satisfy the Euler characteristic.There is no simply connected polyhedron that meets these requirements because they do not satisfy the Euler characteristic.There is no simply connected polyhedron that meets these requirements because they do not satisfy the Euler characteristic.
What has 7 vertices's 7 faces and 8 edges?
The numbers given do not satisfy the Euler characteristic for a polyhedron. There is, therefore, no such polyhedron.
What shape has 8 faces 3 edges and 7 vertices?
The numbers given do not satisfy the Euler characteristic for a polyhedron. There is, therefore, no such polyhedron.
Does a polyhedron have 10 faces 28 edges and 18 vertices?
No. The given numbers do not satisfy the Euler characteristic for a simply connected polyhedron.
Can a polyhedron have 20 faces 30 edges and 13 vertices?
No. The numbers do not satisfy the Euler characteristic.
Can a polyhedron have 10 faces 20 edges and 15 vertices?
No. The numbers are not consistent with the requirements of the Euler characteristic.
What has 3 rectangular faces 9 edges and 6 vertices?
It cannot be a polyhedron because it does not satisfy the Euler characteristic.
What has 12 faces 10 edges 20 vertices?
Not any normal polyhedron since the numbers are contary to the Euler characteristic.
What shape has 9 faces 18 edges and 10 vertices?
There can be no such polyhedron since the given numbers are not consistent with the Euler characteristic.
How have 1edge and 2 faces and 8 sides?
There can be no polyhedron with the given number of edges, faces and sides since they do not satisfy the Euler characteristic.
What has 6 faces 8 edges and 8 corners?
There can be no simply connected polyhedron with those values since they are not consistent with the Euler characteristic.
What figure has 5 faces and 8 edges and 4 vertices?
Since the numbers do not satisfy the Euler characteristic, it is not a simply connected polyhedron.
