No. You cannot convert cubic meters in length, width, and height without any further information.
Without further information it is not possible to answer the question.
You can't if you don't what the height and width is.
This question cannot be answered sensibly. A metre square is a measure of area, with dimensions [L2]. A height is a linear measure, with dimensions [L]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.
You do not convert height to metres, you MEASURE height in metres (or centimetres, or feet or miles).
To convert cubic meters (m³) to square meters (m²), you need to specify the height or depth of the space. Without that information, you cannot directly convert 55 m³ to m², as m² measures area while m³ measures volume. For example, if you have a height of 1 meter, then 55 m³ would equal 55 m².
No, it is not possible to accurately determine someone's height from a picture without additional information or context.
I'm sorry, but I don't have any information about Anna's height. If you can provide more context or details about who Anna is, I might be able to help further!
Without knowing your height, it would be impossible to tell. If you are, say, 5' 8" to 5' 11", you are not obese. If you happen to be 5' 2", then you might have a problem. ---- For further information, please see the related page link, further down this page, listed under "Related Questions."
Weight is worked out on height not age. For further information about weight in relation to height, see the page link, further down this page, listed under "Related Questions."
You cannot without a lot more information about the shape.
The volume of a cone is given by the formula V =⅓πr2h where r is the radius of the base and h is the vertical height. If the volume is known there are still two unknowns, r and h and therefore the problem cannot be solved without at least one further piece of relevant information.
For further information, please see the related link, further down this page, listed under "Related Questions."