20 +30 + 50
100/3-1, 100/3 and 100/3+1 that is, 99, 100 and 101.
To find five numbers with a mean of 20, we can use the formula for mean: Mean = (sum of all numbers) / (total number of numbers). Since we have five numbers, the sum of the numbers should be 20 * 5 = 100. To find five numbers that add up to 100, we can choose any set of five numbers that sum up to 100, such as 10, 20, 30, 15, and 25.
The numbers are 51.5 and 48.5
The sum of these composite numbers, including 100, is 3989.The sum of all numbers between 1 and 100 is 5,050. From this we need to subtract the sum of 1 plus all the prime numbers below 100. The sum of the primes is 1,060. Subtracting (1 + 1060) or 1,061 from 5,050 yields 3,989.
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
You add the numbers in a loop. Here is an example in Java:int sum = 0;for (int i = 1; i
79 + 19 + 2
2 and 3. 2 + 6 = 8, the sum. 6 / 2 = 3, the quotient.
Prime numbers having the sum of 100 are 47 + 53, 71 + 29, 89 + 11, 97 + 3, 83 + 17, and 41+ 59.
96+98+100 = 294
No.
The sum of prime numbers between 1 and 25 is 100. 2 + 3 + 5 + 7 + 11 +13 +17 + 19 + 23 = 100