Yes I can. Where the lines intersect, (7 - 3x) = (2x - 3). Add (3 + 3x) to both sides of this equation, giving: 10 = 5x or x = 2. Plug x=2 back into either one of the given equations to find 'Y'. If we've done our work correctly, we should get the same 'Y' regardless of which equation we plug x=2 into. And in fact we do: From the first one: Y = 7 - 3x = 7 - (3 times 2) = 7 - 6 = 1 From the second one: Y = 2x - 3 = (2 times 2) - 3 = 4 - 3 = 1 So the two lines intersect at the point ( 2, 1 ).
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
The intersection is (-2, 6)
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Theorem: If two lines intersect, then exactly one plane contains both lines. So, when two or more lines intersect at one point, they lie exactly in the same plane. When two or more lines intersect at one point, their point of intersection satisfies all equations of those lines. In other words, the equations of these lines have the same solution, which is the point of intersection.
The coordinates of the point of intersection must satisfy the equations of both lines. So these coordinates represent the simultaneous solution to the two equations that that represent the lines.
The coordinates of the point of intersection represents the solution to the linear equations.
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
x + y = 6x + y = 2These two equations have no common point (solution).If we graph both equations, we'll find that each one is a straight line.The lines are parallel, and have no intersection point.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
The intersection is (-2, 6)
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Theorem: If two lines intersect, then exactly one plane contains both lines. So, when two or more lines intersect at one point, they lie exactly in the same plane. When two or more lines intersect at one point, their point of intersection satisfies all equations of those lines. In other words, the equations of these lines have the same solution, which is the point of intersection.
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
A system of equations will have no solutions if the line they represent are parallel. Remember that the solution of a system of equations is physically represented by the intersection point of the two lines. If the lines don't intersect (parallel) then there can be no solution.
Solve the two equations simultaneously. The solution will be the coordinates of the point of intersection.