6/3=2
8x2=16
16-8
no
Its immposible.
4+2=6 6-3=3 3-1 2
((6/3)+6)3
3! = 6.
By using: (3*6)+(3*2) = 24
3 quarters, 2 dimes, 1 nickel.
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
(1+1+1)! = 3! = 3x2x1 = 6... :)
Throw away the '3', the '5', and either of the '6's.
1/2, 3/6, 4/8
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s