The simplest solution is to find two numbers, L and B, so that a rectangle with length L and breadth B has an area of L*B = 18 and a perimeter of 2*(L + B) = 28.
The solution is L = 12.56776 and B = 1.43224 to 5 decimal places.
An alternative is a parallelogram with sides of 9 and 5 units (9 + 5 = 14 = half perimeter), flexed so that the vertical distance between the long sides is 2 units.
a 4*5 rectangle.
Perimeter and area are not sufficient to determine the shape of a figure.
a rectangle
Yes.
The simplest shape is a 6ft*3 ft rectangle.
Yes if you
a 4*5 rectangle.
Perimeter and area are not sufficient to determine the shape of a figure.
Actually it is possible.
a rectangle
It depends. What shape is it? And is it equilateral or not?
Yes.
Yes. Use excel with 18 boxes. Offsetting the boxes will get you the right answer.
The simplest shape is a 6ft*3 ft rectangle.
No, because you would need a calculation os 3 to make a calculation of 6, and 18 and 20 aren't friendly to one another!
No, the size of the perimeter and the area of a shape are not always directly related. For example, a circle with a small perimeter can have a larger area compared to a square with a larger perimeter. The area of a shape is determined by the size of its dimensions, whereas the perimeter is the sum of the lengths of its sides.
The perimeter and area of a shape do not provide sufficient information. With a given perimeter, the largest area that you can enclose is a circle, but you can then flatten the circle to reduce its area. Similarly, in terms a of quadrilaterals, a square has the largest area, but it can be flexed into a rhombus whose area can be made as small as you like. All that can be said is that there is no shape with a perimeter of 12 units whose area is 12 square units.