C represents one atom of Carbon.
O2 represents two atoms of Oxygen, joined together.
One atom of Carbon plus two atoms of oxygen, all joined together, becomes one molecule of carbon dioxide, which has the chemical symbol CO2
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Sorry, but there is no realistic chemical reaction to 'dissociate' CO2 in elements.
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
C(s) + O2(g) -> CO2(g)
CH3CH2OH + 3O2 --> 2CO2 + 3H2O Reactants: 6 H; 2 C; 7 O. Products: 6 H; 2 C; 7 O
This is a chemical calculation. 2.5 moles will C reacting with O2.
1c+1o2->1co2
C+O2 →CO2
Carbon plus Oxgen gives Carbon dioxide. C + O2 = CO2
C + O2 -> CO2Because oxygen is a gas, it exists in a normal state bonded to another oxygen.
carbon and oxygen
The reactants are Carbon (C) and Oxygen (O). The product is Carbon dioxide (CO2) The equation (balanced) is (C + O2 -----> CO2)
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
c+o2 = co2
C(s) + O2(g) -> CO2(g)
C+co2 = 2co
If you add heat to it, it will separate into C and O2