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Q: Corey's harvests 3000 bananas The market is 1000 miles away she can only carry 1000 bananas at a time She has to eat one banana for each mile she walks. How many bananas can she get to the market?
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A banana grower wants to transport his 3000 bananas 1000 miles across the desert to the market All he can use is his one camel which can carry 1000 bananas at once but it needs to eat one banana to?

i made the camel walk 1 km drop its load and then come bak pick the nxt thousand and drop it after 1km so for 1st 1000 bananas : camel requires bananas ( to and fro) nxt 1000 dates : 2bananas and last 1000 only 1 banana required no need to come back so the camel can travel 1km using 5 bananas . after travelling 200kms u will lose 1000 bananas (200*5), so for the nxt each kilometre camel requires only 3 bananas . so in that way using 999 bananas u can reach 533 kms( 333 + 200). now u hav 1001 bananas left with u,leave that 1 banana there and go the remaining distance u can take 533 to other side


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How many bananas can Corey get to the marketplace?

This question comes from the Math Central website: "The problem is: Corey Camel's harvest, worth its weight in gold, consists of 3000 bananas. The market place where the stash can be cashed in is 1000 miles away. However, Corey must walk to the market, and can only carry up to 1000 bananas at a time. Furthermore, being a camel, Corey eats one banana during each and every mile she walks (so Corey can never walk anywhere without bananas). How many bananas can Corey get to the market? As a reminder we're told to save our notes as we work on the problem. I can't get past an answer of 0. Corey can only carry 1000 bananas and he eats one for every mile so by the time he gets to the market he has 0 bananas to sell and 0 bananas to eat to get him home."The answer given is 533. A long explanation of the math is also given.


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What is the answer for Corey the camel problem?

How many bananas does he have total to begin with? I am just assuming that he has 3,000 bananas, can carry 1,000 at a time, and has to travel 1,000 miles to get to the market, eats 1 banana every mile, can't go anywhere without bananas, and can store them any place along the way. The largest amount he can get to the market is 533 1/3 bananas. This is how to get it: First thing, he gathers 1,000 bananas, then goes 200 miles, drops off 600 bananas there, then goes back. He grabs another 1,000 and at the 200 mile mark, where he left 600 bananas, he gets another 200 bananas (leaving 400 at the 200 mile mark). Now he has 1,000 bananas again. Now lets divide 1,000 into thirds: 333 1/3 to get to the next (storehouse?), 333 1/3 to store, and 333 1/3 to get back to the previous storehouse (so now he has 400 bananas at the 200 mile mark and 333 1/3 bananas at the 533 1/3 mile mark). So now he goes back to the 200 mile mark, picks up 200 bananas because he's out of bananas, and gets back to his oasis. Now for the final 1,000 bananas. He gets 1,000 bananas, goes 200 miles, picks up the last 200 bananas (so now he's back to 1,000 bananas), goes 333 1/3 miles, picks up the 333 1/3 bananas there (again has 1,000 bananas), and goes to the market. At the market, he has 533 1/3 bananas.


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