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No. Complex numbers is the highest set of numbers you can go, and there are no sets outside of complex numbers.

Q: Could anyone list numbers not in the set of complex numbers?

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No, because the list is infinite. However, you can find them for yourself since the nth triangular number is n(n+1)/2

On the list of choices posted with the question, there is nothing that could be placed between two odd numbers.

That's an infinite list. You could divide 2556 by 2.

No. If I give you a list of non significant numbers, then there will be a first number in the list and it will therefore be a significant number as it's the first one of the list, so I'd have to remove it from the list. This would then leave the second non significant number as the first one in the list which gives it significance, so I'd have to remove it as well. The net result is that I'd have to remove all the numbers from the list of non significant numbers leaving it empty, that is, there are no non significant numbers.

It is impossible to list all the prime numbers as there are an infinite number of them. The list of prime numbers starts: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, ... Suppose you could list all the prime numbers and have done so - there is no prime number which is not on the list. Multiply them all together and add 1. This number is not divisible by any of the listed prime numbers as there is always a remainder of 1. So either this new number is a prime number, or there is another prime number not listed which will divide into it. Which means that the list was not all the prime numbers; meaning it is impossible to list all the prime numbers.

Related questions

Negative numbers do not have any factors.

No. Not on the passenger list. Perhaps on the staff list, which you could do an online search for.

You could use a bubble sort.

No, because the list is infinite. However, you can find them for yourself since the nth triangular number is n(n+1)/2

On the list of choices posted with the question, there is nothing that could be placed between two odd numbers.

That's an infinite list. You could divide 2556 by 2.

No. If I give you a list of non significant numbers, then there will be a first number in the list and it will therefore be a significant number as it's the first one of the list, so I'd have to remove it from the list. This would then leave the second non significant number as the first one in the list which gives it significance, so I'd have to remove it as well. The net result is that I'd have to remove all the numbers from the list of non significant numbers leaving it empty, that is, there are no non significant numbers.

In an unordered list, you usually just bullet the list, but in an ordered list it is typical to just put a period after a letter or number. However, if you are using really complex nested lists, then sometimes the style is switched up depending on the nesting style and how deep you are. Occasionally, people will use parentheses around numbers in a list.

To find the average of a list of numbers, add the numbers and divide by the number of numbers in the list.

It is impossible to list all the prime numbers as there are an infinite number of them. The list of prime numbers starts: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, ... Suppose you could list all the prime numbers and have done so - there is no prime number which is not on the list. Multiply them all together and add 1. This number is not divisible by any of the listed prime numbers as there is always a remainder of 1. So either this new number is a prime number, or there is another prime number not listed which will divide into it. Which means that the list was not all the prime numbers; meaning it is impossible to list all the prime numbers.

what is the ratio or prime numbers to composite numbers in this list/10,11,2,13,14,15,16,1,7,18,19,20,21

67, 76