yes like say you had 10 ten times so it would be 100 so you devide by ten and get 10 you can also say you have 9 and 11 then add it together and get 20 / by 2 and get 10
if by Numbers you mean Integers, then the answer is TRUE. if it is real numbers, then it is false.
Here's a clue. Ten needs to be one of the numbers.
he mean of ten numbers is 58. If one of the numbers is 40, what is the mean of the other nine?
It means write the next ten numbers that come after this.
The set of odd numbers between zero and ten includes the numbers 1, 3, 5, 7, and 9. These numbers are characterized by not being divisible by 2, and they are all positive integers less than ten. This set can be expressed as {1, 3, 5, 7, 9}.
20C10 = 184,756
There are 4 possible answers: (7, 7, 10, 13, 13) (7, 8, 10, 12, 13) (7, 9, 10, 11, 13) (8, 8, 10, 10 14).
To have a median of ten with five numbers, the third number (when arranged in ascending order) must be 10. One possible set of five numbers could be 5, 8, 10, 12, and 15. This set is arranged in increasing order, and the middle number is indeed 10. Other combinations are possible as long as the third number remains 10.
The mean increases by 10.
They are members of the infinite set of numbers of the form 2520*k where k is an integer. Since the set is infinite, it is not possible to list them.
38.5
6 + 14