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Numeric answerThe chances of choosing a 'K' for the first character is 1/26 (one chance out of twenty-six letters).

The chances of choosing a '9' for the second character is 1/10 (one chance out of ten digits).

To get the probability of both events happening at once, multiply the two individual chances:

1/26 * 1/10 = 1/260

Another way to think about it...We know that out of all possible combinations of letters and numbers, there is only one way to form the password "K9"

This means that if we figure out the number of possible combinations, we will know the chances of randomly picking any one combination.

We have 26 possible choices for the first digit. This is easy to know, since there are 26 letters in the alphabet. Now we just need to combine them with all possibilities for the second digit.

So if we pick a 0 for the second digit, that gives us 26 possible choices...

Now if we pick a 1 for the second digit, that gives us another 26 possible choices, for 52 total...

If you keep going along these lines, you see that there are 26 total possibilities for each possible second digit. Since there are 10 different digits, we can figure that there are 10 * 26, or 260, total possibilities.

So for each combination of two characters (including "K9"), you have 1 chance out of 260 possibilities to pick it.

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Q: Create a password of 2 characters and randomly select a letter of the alphabet for the first and a digit from 0 through 9 for the second character What is ithe probabilty that the password is K9?
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