just create a mathematical equation using 1964 such as 1x1964 2x1964 3x1964 4x1964 or 1964/1 1964/2 etc
((9/9)-(9/9)+(9/9)) = 1
If you mean: x2+2x+1 = 0 then it is a quadratiic equations whose solutions are equal because x = -1 and x = -1
Assume something (e.g. equations) using k then prove k+1 using k.
All of them, but it does depend on what operators are allowed.
(2+3)(5)=(4)(6)+1 Is this what you mean?
100-1 101-2 102-3
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. .
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
The difference of algebra and algebra 1 is that in algebra they teach you the basics. For example, they teach you about variables, graphs, how to find slopes. In algebra 1 they start using equations and and teach you how to work longer equations and all that jazz.
Yes, some equations have as many as ten. There is a very rare equations that only two people have seen that has 1 billion solutions.
1= 3/3 2=(3+3)/3 3= 3+3-3 4=(3+3+3+3)/3 5=(3+3+3+3+3)/3 6=(3+3+3+3+3+3)/3 and so on
Imaginary numbers are only ever used when you are using the square roots of negative numbers. The square root of -1 is i. You may find imaginary numbers when you are finding roots of equations.
You multiply one or both equations by some constant (especially chosen for the next step), and add the two resulting equations together. Here is an example: (1) 5x + 2y = 7 (2) 2x + y = 3 Multiply equation (2) by -2; this factor was chosen to eliminate "y" from the resulting equations: (1) 5x + 2y = 7 (2) -2x -2y = -6 Add the two equations together: 3x = 1 Solve this for "x", then replace the result in any of the two original equations to solve for "y".
If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
There is no quadratic equation that is 'linear'. There are linear equations and quadratic equations. Linear equations are equations in which the degree of the variable is 1, and quadratic equations are those equations in which the degree of the variable is 2.
The two equations must involve 2 unknowns. If there is only 1 unknown, the 2 equations must be the same (or one a simple multiple of the other). Using one of the equations, turn it into a form where one of the unknowns is expressed in terms of the rest of the equation. Then use this expression to substitute for that unknown in the other equation. This other equation now involves only one unknown so you can simplify it to find its value. Use that value in either of the original equations to find the other value. Example 2x + 3y =8 and x-y=-1. From the 2nd equation you have x=y-1 and use that in the 1st equation to get 2(y-1)+3y=8, which depends only on y. Simplify to get 2y-2+3y=8, so 5y=10 and y is 2. Use that in either of the 1st pair of equations to get 2x+6=8 (or from the other equation x-2=-1) Either way, x=1.
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58
Suppose you have n linear equations in n unknown variables. Take any equation and rewrite it to make one of the variables the subject of the equation. That is, express that variable in terms of the other (n-1) variables. For example, x + 2y + 3z + 4w = 7 can be rewritten as x = 7 - 2y - 3z - 4w Then, in the other (n-1) equations, plug in that value for the variable and simplify (collect like terms). You will end up with (n-1) equations in (n-1) unknown variables. Repeat until you have only one equation in 1 variable. That gives you the value of one of the variables. Plug that value into one of the equations from the previous stage. These will be one of two equations in two variables. That will give you a second variable. Continue until you have all the variables. There are simpler methods using matrices but you need to have studied matrices before you can use those methods.
Mariah - 1987 Equations 1-1 was released on: USA: 2 April 1987
No because there are no equations there to choose from.
Linear Equations are equations with variable with power 1 for eg: 5x + 7 = 0 Simultaneous Equations are two equations with more than one variable so that solving them simultaneously