answersLogoWhite

0

1, 2, 4, 5 = 30

User Avatar

Wiki User

∙ 12y ago

What else can I help you with?

Related Questions

How do you create equations for the numbers 1-100 using 1964?

just create a mathematical equation using 1964 such as 1x1964 2x1964 3x1964 4x1964 or 1964/1 1964/2 etc


Bedmas equations from 1-100 using 1 and 4 and 8 and 9?

100


How do you create equations for the numbers 1-10 using 3 using order of operation?

To create equations for the numbers 1-10 using the number 3 and the order of operations, you can apply various arithmetic operations like addition, subtraction, multiplication, and division. For instance: 1 = (3 - 3) + 1 2 = (3 - 1) 3 = 3 4 = (3 + 3) - 2 5 = (3 * 2) - 1 6 = 3 * 2 7 = 3 + 3 + 1 8 = (3 * 3) - 1 9 = 3 * 3 10 = (3 * 3) + 1 This method allows for creative combinations while adhering to the order of operations.


How do you get the answer 1 using 6 nine's in a equations?

((9/9)-(9/9)+(9/9)) = 1


What is another name for solution in equations using x squared 2x plus 1 0?

If you mean: x2+2x+1 = 0 then it is a quadratiic equations whose solutions are equal because x = -1 and x = -1


How do you solve mathematical induction problems?

Assume something (e.g. equations) using k then prove k+1 using k.


How many of numbers from 1 to 9 can you create using only four 4'S?

All of them, but it does depend on what operators are allowed.


How divide 100 rupees into w notes with out using 2 rupees only using1rupe5rupe10rupe note?

To divide 100 rupees into ( w ) notes using only 1 rupee, 5 rupee, and 10 rupee notes without using 2 rupee notes, you can set up a system of equations. Let ( x ) be the number of 1 rupee notes, ( y ) be the number of 5 rupee notes, and ( z ) be the number of 10 rupee notes. The equations would be ( x + y + z = w ) and ( x + 5y + 10z = 100 ). By varying ( y ) and ( z ), you can find different combinations of notes that satisfy these equations.


How do you create equations for the numbers 1-10 using the number 3 only?

1= 3/3 2=(3+3)/3 3= 3+3-3 4=(3+3+3+3)/3 5=(3+3+3+3+3)/3 6=(3+3+3+3+3+3)/3 and so on


X plus y equals 1 solve?

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. .


X plus y equals 1 for y?

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.


How do you solve systems of equations using substitution?

3(5x-2y)=18 5/2x-y=-1