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Distance of fall in T seconds = 1/2 g T2

Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 meters

Height of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters

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14y ago
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Q: David drops a ball from a bridge at an initial height of 70 meters what is the height of the ball to the nearest tenth of a meter exactly 2 seconds after he releases the ball?
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