I think the wave will either refract/reflect off the object and it may even cancel out the wave and will stop moving/traveling. Hhope this was veryy helpful to u guys!!
;-) :-0 ha ha :-8
You get total internal reflection. That is, the incident beam bounces off the interface back into the medium.
left
yes
The angle of incident is 45 degrees. The incident and reflected ray have the same magnitude and if the sum of the magnitudes is 90 degrees the incident is 45 degrees.
The angle of incidence equals the angle of reflection. Therefore, if your angle of incidence is 15 degrees, your angle of reflection equals that also. If it is 45 degrees, your angle of reflection is also 45 degrees, and so on.
That happens when the incident ray is perpendicular to the surface at the point of incidence.
The angle of incidence is the angle between the incident ray and the normal (perpendicular) to the reflecting surface.
You get total internal reflection. That is, the incident beam bounces off the interface back into the medium.
It is the angle between an incident ray and the perpendicular to the surface at the point of incidence.
left
The incident angle to the Mirror will be 10 deG.
yes
The angle of incidence equals the angle of reflection. Therefore, if your angle of incidence is 15 degrees, your angle of reflection equals that also. If it is 45 degrees, your angle of reflection is also 45 degrees, and so on.
The angle of incident is 45 degrees. The incident and reflected ray have the same magnitude and if the sum of the magnitudes is 90 degrees the incident is 45 degrees.
That's the angle of " incidence ".
We know angle of incidence = angle of reflection. Hence, angle of incidence will be 24/2 = 12 degrees. (which is also angle of reflection)
The incident ray and the normal .