Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0.
Now, make a truth table as follows
A2 A1 A0 S5 S4 S3 S2 S1 S0
0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 1
0 1 0 0 0 0 1 0 0
and so on.......
Finally we'll get
S0 = A0
S1 = 0
S2 = A1 A2(bar)
S3 = A0 [ A1 XOR A2]
S4 = A2 [A1(bar) + A0 ]
S5 = A1 A2
http://tinypic.com/view.php?pic=23ku43c&s=5 see this
if you want to use 8*3 encoder than you must the design the circuit according to variable and with the help of k-map and you can not construct the circuit of 8*3 encoder using 7432 (which is or gate ic) only. you need AND gate 7408 and may be NOT 7404 gate according to design.
The S transform in circuit analysis and design is method for transforming the differential equations describing a circuit in terms of dt into differential equations describing a circuit in terms of ds. With t representing the time domain and s representing the frequency domain.Usually the writing of the time domain equations for the circuit is skipped and the circuit is redrawn in the frequency domain first and the equations are taken directly from this transformed circuit. This is actually much simpler and faster than transforming the time domain equations of the circuit would be.The S transform and Laplace transform are related operations but different; the S transform operates on circuits and describes how they modify signals, the Laplace transform operates on signals.
We need STA in VLSI - ASIC because of these reasons: # To analyze the timing relationships of a given circuit to verify that the circuit works at the specified frequency (verification). # 100 % path coverage is possible because no design specific pattern is required. # You can't achieve the clock speed without it.
Boolean algebra is used in logic circuits. Using And, Nor, Xor and Nand gates to determine the state of an output, dependant on the condition of various inputs. Or, if you like, to make a fixed decision based on the inputs. When designing a logic circuit, it is easy to get confused by too many steps in the process to get the answer that you want. By using Boolean algebra, the steps can be rationalised and reduce to the minimum number of steps, before committing to a finished physical circuit.
Design and draw a combinational circuit using AND-OR-NOT gates that accepts 4 input bits, and produces two bit output; the first of the two bits is set to 1 if the number of 1's in the input is even; and the second of the output bit is set to 1 if the input have 3 or more (all four) 1 bits.
A: FIRST step is form a flow chart. whereby decisions can be followed
Any hardware whatsoever satisfies the conditions of this question ... as long as it hasthree input lines ... since the question neglects to specify what it wants the circuit to dowith the 3-bit input number.
Because it is a very efficient language for describing their operation as well as a tool to assist in design optimization (reducing the cost of the circuit when built).
There is no need for a combinatorial circuit to multiply a number by two. A binary number, left shifted one place, is twice the original binary number. The specific answer to the question is that you would connect the three input lines to the three high order output line of four output lines, and connect the low order bit of the four output lines to logic 0. If the three input lines were labelled A, B, and C, the output would be A, B, C, and 0.
Advantages are 1: it reduces number of wires. 2:it reduces circuit complexity and cost. 3:it simplifies logic design. 4:we can implement many combinational circuits using MUX. 5:it does not need kmaps and simplification.
here i vil the equation for that design dat u implement with the gates. This Anser is for only Q(a) The euation is a bar.d bar+a.b bar.d+a.c.d
VHDL is a system level programming language and Verilog is a circuit level programming language. VHDL can be viewed as a language written in programmer's point of view. In that manner it is better than VHDL. For example, to write a code for a simple combinational circuit, we need to define from the circuit level in Verilog i. e. FET level. But in VHDL, we can directly take several smaller components and combine them to trealize the circuit. That means, one need not have a knowledge of analog circuits to design something in VHDL. He only needs to know the behavior of the desired design.
An xor gate with 1 i/p being the original clk signal.The other i/p is the clk delayed by cycle_time/4.The delay can be achieved by buffer.The o/p is now double the clk freq.
nothing in electronic logic circuits.relay logic circuits often use solenoids as the electromagnetic coils of the relays.
design and implementation of a buffer circuit using operational amplifier
First you start with an idea of what the circuit will do.