first create truth table, inputs should be combination of 3 bits i.e 8 possible combination. the outputs are the square of each input. you need 6 bits for the outputs since the square of 7 is 49 which is binary notation 49 is (110001) hence 6 bits. same goes for the other inputs. when the table is complete. find the Boolean function that drives each bit, preferably by K-maps to minimize the logic. Then from the equations, simply draw the circuit by using the necessary logic gates. There will be 3 inputs and 6 outputs for the overall circuit.
Very easy but tedious. have fun
Any hardware whatsoever satisfies the conditions of this question ... as long as it hasthree input lines ... since the question neglects to specify what it wants the circuit to dowith the 3-bit input number.
Because it is a very efficient language for describing their operation as well as a tool to assist in design optimization (reducing the cost of the circuit when built).
here i vil the equation for that design dat u implement with the gates. This Anser is for only Q(a) The euation is a bar.d bar+a.b bar.d+a.c.d
There is no need for a combinatorial circuit to multiply a number by two. A binary number, left shifted one place, is twice the original binary number. The specific answer to the question is that you would connect the three input lines to the three high order output line of four output lines, and connect the low order bit of the four output lines to logic 0. If the three input lines were labelled A, B, and C, the output would be A, B, C, and 0.
Simply: design an application, that accept one number, then put it in a loop that repeat is ten times.
Design and draw a combinational circuit using AND-OR-NOT gates that accepts 4 input bits, and produces two bit output; the first of the two bits is set to 1 if the number of 1's in the input is even; and the second of the output bit is set to 1 if the input have 3 or more (all four) 1 bits.
A: FIRST step is form a flow chart. whereby decisions can be followed
Any hardware whatsoever satisfies the conditions of this question ... as long as it hasthree input lines ... since the question neglects to specify what it wants the circuit to dowith the 3-bit input number.
Because it is a very efficient language for describing their operation as well as a tool to assist in design optimization (reducing the cost of the circuit when built).
Advantages are 1: it reduces number of wires. 2:it reduces circuit complexity and cost. 3:it simplifies logic design. 4:we can implement many combinational circuits using MUX. 5:it does not need kmaps and simplification.
here i vil the equation for that design dat u implement with the gates. This Anser is for only Q(a) The euation is a bar.d bar+a.b bar.d+a.c.d
VHDL is a system level programming language and Verilog is a circuit level programming language. VHDL can be viewed as a language written in programmer's point of view. In that manner it is better than VHDL. For example, to write a code for a simple combinational circuit, we need to define from the circuit level in Verilog i. e. FET level. But in VHDL, we can directly take several smaller components and combine them to trealize the circuit. That means, one need not have a knowledge of analog circuits to design something in VHDL. He only needs to know the behavior of the desired design.
An xor gate with 1 i/p being the original clk signal.The other i/p is the clk delayed by cycle_time/4.The delay can be achieved by buffer.The o/p is now double the clk freq.
nothing in electronic logic circuits.relay logic circuits often use solenoids as the electromagnetic coils of the relays.
There is no need for a combinatorial circuit to multiply a number by two. A binary number, left shifted one place, is twice the original binary number. The specific answer to the question is that you would connect the three input lines to the three high order output line of four output lines, and connect the low order bit of the four output lines to logic 0. If the three input lines were labelled A, B, and C, the output would be A, B, C, and 0.
design and implementation of a buffer circuit using operational amplifier
First you start with an idea of what the circuit will do.