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Firstly, the 1st row has 21 logs, the last has 15. The difference is 6, though the number of terms is 7. (21 - 14 = 7), and 7/7 (per row) is 1. Thus, it decreases by 1 every row. So we have an addition problem:

21 + 20 + 19 + 18 + 17 + 16 + 15 = 3(36) + 18 = 108 + 18 = 126.

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Q: Determine the number of logs in the pile if there are logs stacked in a pile in which there are 21 logs in the bottom row and 15 logs in the top row if there are seven rows?
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