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For this type of problem we use an I.C.E. diagram

C6H5CO2H

C6H5CO2

H3O

0.461 M

?

?

-X

+X

+X

0.461 - X

+X

+X

Ka of C6H5CO2H is 6.5 x 10-5.

Ka = [C6H5CO2][H3O]/[C6H5CO2H]

6.5 x 10-5 = x2/(0.461 - x)

after manipulation

X2+ (6.5 x 10-5)x - (2.99 x 10-5)

--> Plug in the Quadratic Formula

X = +/- 0.0055

[H3O] = 0.0055

-Log(0.0055) = pH

pH = 2.26

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Q: Determine the pH of a 0.461 m c6h5co2h m solution if the ka of c6h5co2h is 6.5 x 10-5?
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