9 - (4 - 2) * 1 = 7
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
20-2n when n = 7. just take 20-2(7) replace n with 7. then use the PEMDAS rule. 2(7) = 14, then 20-14 = 6
(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!
since 4 is 2 times 2 just double 7 twice: 7 doubled = 14 and then 14 double = 28
use the tens place to multiply by 2, then use the number to subtract the ones place.The answer can be divided by 7, if not it will be 0.use 490 as an example.9x2=18.18-4=14.14 divided by 7 is 2. so 49 can be divide by 7
9 - (4 - 2) * 1 = 7
7, 2 and 0
Use the formula n(n-1)/2 --> 7(7-1)/2 = 7(6)/2 = 42/2 = 21.
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
1 x 7 plus 2 x 7 is the same as 3 x 7
(6+7)x2=26... 26-(9-7)=24 !
Use the quadratic formula... [-b +/- sqrt(b^2 - 4ac)] / 2a You use this formula when you have a quadratic equation ( ax^2 + bx + c). In this case: a=2, b= -7, c= -86. Plug into the formula... [7 +/- sqrt(7^2 - 4(2)(-86))] / 2(2) = [7 +/- sqrt (737)] / 4 Equating this you get x = 8.537 and x = -5.037
13 ft 7 in+ 2 ft 7 in=
6 x 7 is equal to 2 x 3 x 7. If you find the solution to 3 x 7, you can multiply it by 2 to get 6 x 7.
2,792
most likely 2/7