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Divide the roman numeral dxxii by iii in roman numerals what would be your answer?
Wiki User
∙ 14y ago
The answer is 174.
DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIVDXXII/III =
= D/III + X/III + X/III + II/III =
= (CxV)/III + (III + I/III) + (III + I/III) + II/III =
= Cx(V/III) + VII + I/III =
= Cx(I + II/III) + VII + I/III =
= C + (CxII)/III + VII + I/III =
= C + ((XxX)xII)/III + VII + I/III =
= C + Xx(XxII)/III + VII + I/III =
= C + Xx(VI + II/III) + VII + I/III =
= C + LX + (XxII)/III + VII + I/III =
= C + LX + VI + II/III + VII + I/III =
= CLXXIV
Wiki User
∙ 14y ago
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