By any of its factors which are: 1, 3, 107 and 321

107 is a prime number and is divisible only by 1 and 107.

It is divisible by: 1, 53, 107 and 5671

It is and the answer is 107.

It is any member of the set of numbers of the form 107*k where k is an integer.

321 is divisible by these four numbers: 1, 3, 107, 321.

5671 is not divisible by 7. 1, 53, 107, 5671

The number 5,671 is evenly divisible by these numbers: 1, 53, 107 and 5,671.

535 is divisible by 1, 5, 107, 535

By itself and 1 because it's a prime number

The factors of 535 are: 1, 5, 107 & 535.

1, 2, 4, 107, 214, 428

yes 107 x 9 = 963

1, 2, 3, 6, 107, 214, 321, 642

No: 643 divided by 6 is 107 with remainder one.

Yes, 428 divided by 4 equals 107.

1, 2, 4, 8, 107, 214, 428, 856

642 is composite. It is divisible by 2, 3, 107, 214, and 321.

107 is a prime number. Its only factors are 1 and itself. It is not a composite number.If 107 has a factor is must be less than root of 107 ie less 11. Prime numbers below 11 are 2,3,5,7 As 107 is not divisible by any of these it is a primeyes, you cant divide 107 by anything

Since all numbers between 61 and 107 are less than 367, none of them are divisible by 367. 84 is a multiple of 3, 6 and 7 in that range.

101, 103, 107, 109 not 105 as that is divisible by 5

214 321 428 535 642 749 856 963 1,070 and so on ...

105 is not a prime number among them. It is because it is divisible by 5.

84 is the only one; it is divisible by 28 the lowest common multiple

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