it depends on how we are connecting them.if 5 1 ohm resistors are connected in series then the equivalent resistance is 5 ohms.if they are connected in parallel then the equi resistance is 1/5 ohms.
The effective resistance of three resistors, 120 ohm, 60 ohm, and 40 ohm, in parallel is 20 ohms.RP = 1 / sum (1 / RN)RP = 1 / (1 / 120 + 1 / 60 + 1 / 40)RP = 20The voltage applied, 120V, does not change the outcome. The power, however, of the three resistors is 120W, 240W, and 360W respectively. This is a lot of power, so please do not attempt to do it for real.
It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.
Resistors are color coded to denote the value of the resistor as well as the multiplier. In your case a 470 ohm would be colored as Yellow Violet Brown corresponding to 4, 7 and a multiplier of 10^1.
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
1.5 ohms. Two 3 ohm resistors in parallel.
Only if you connect then in series. RSERIES = Summation1toN (RN) RPARALLEL = 1 / Summation1toN (1 / RN)
4, 1 3 ohm resistor in series with 3 3 ohm resistors in parallel.
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:Total resistance = 3 ohms.Current in the loop = 6/3 = 2 amperesPower dissipated by the 2-ohm resistor - I2R = 8 watts.2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallelThe 12-ohm resistor is irrelevant.4 volts across the 2-ohm resistor.Power dissipated by the 2-ohm resistor = E2/R = 8 watts.
The effective resistance of three resistors, 120 ohm, 60 ohm, and 40 ohm, in parallel is 20 ohms.RP = 1 / sum (1 / RN)RP = 1 / (1 / 120 + 1 / 60 + 1 / 40)RP = 20The voltage applied, 120V, does not change the outcome. The power, however, of the three resistors is 120W, 240W, and 360W respectively. This is a lot of power, so please do not attempt to do it for real.
If they're in parallel, then the resistors have no effect on each other. The current through each one is the same as it would be if the others were not there at all. The current through the 120Ω resistor is 120 volts/120Ω = 1 Ampere. The 60Ω and the 40Ω are red herring resistors.
It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.
Resistors are color coded to denote the value of the resistor as well as the multiplier. In your case a 470 ohm would be colored as Yellow Violet Brown corresponding to 4, 7 and a multiplier of 10^1.
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
To find the effective resistance of resistors connected in parallel, you can use the following formula: 1/Reff = 1/R1 + 1/R2 + 1/R3 + ... In this case, we have three resistors connected in parallel: a 120-ohm resistor, a 60-ohm resistor, and a 40-ohm resistor. 1/Reff = 1/120 + 1/60 + 1/40 To simplify the equation, we need to find a common denominator: 1/Reff = (1/120) + (2/120) + (3/120) 1/Reff = 6/120 Now, let's invert both sides of the equation: Reff = 120/6 Reff = 20 ohms Therefore, the effective resistance of the three resistors connected in parallel is 20 ohms.
The voltage supplying the circuit will be divided across the series resistors in proportion to their resistance. The wattage of the resistors has no effect on the distribution, but if you put an under rated resistor in the circuit, it will fail. For example, if you have a 10v source, and a 1 ohm resistor in series with a 3 ohm resistor, the 1 ohm resistor, being only a quarter of the total resistance, will see a quarter of the voltage, or 2.5 volts. The other 7.5 volts will seen across the 3 ohm resistor. The total power consumed by the circuit is given by P = VI or V2/R or I2R, so for this circuit, the resistors will consume 25 watts (current is 10/4 = 2.5 amps according to Ohms Law), and 10 x 12.5 gives 25 watts. Hope that helps ItAintMe
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.