No. You will always wind up with the same set.
No. It doesn't matter what factors you choose at the beginning, but all the factors should be prime at the end.
No. Every composite number has a unique prime factorization.
the answer is what ever number you choose you have to times it by itself to get a square number.
No, as long as you don't choose one and the number itself.
A friendly number is a number that has a lot of factors depending on the size of the number. For example, eight is a friendly number. Its factors are 8,4,2,1. 7 isn't because its only factors are 7 and 1.
It's the one with more than two factors.
Depending on your definition of proper factors, the set of proper factor factors either doesn't include 1 and/or the number itself for a given number.
To choose a number that is relatively prime to any other number, you need to select a number that has no common factors (other than 1) with those other numbers. One way to ensure this is to choose a prime number. Prime numbers only have two factors: 1 and itself, making them relatively prime to any other number.
We can't answer this accurately if you don't tell us the groups to choose from.
"Factors" are multiplied, not added. Choose any number (except zero) for the first factor. Then divide -9 by that number to get the second factor.
If the number is odd, that's the answer. If the number is even, write down all the factors and choose the largest one that is odd.
Because a prime number only has two factors: one and the number itself.