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Divide the height of the ramp by the length of the ramp (rise over run).
c^2 = a^2 + b^2 c = sqrt(a^2 + b^2) = sqrt(40^2 + 81^2) = sqrt(8161) = 90 inches
a2 +b2=c2102 + 152 =c2c=18.03 feet
it is a relatively shallow ramp. every single unit that it gains in height, it makes an equivalent TEN units in length
I think since a ramp is a rectangular pyramid you would use the formula Volume= one-third times length times width times height
You are an avid skateboarder and just skated down a ramp. You want to find the distance you traveled. The height of the ramp at its tallest part is 40 inches and the horizontal length is 81 inches. Calculate the distance, to the nearest whole inch, you traveled down the ramp.
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
Divide the height of the ramp by the length of the ramp (rise over run).
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
Its the reciprocal of the sine of the ramp angle. > 1 / ( sin ( ramp angle ) )
yes
if the ramp forms a very steep gradient, definately the car will roll for a longer distance. On the contrary, if the gradient formed by the ramp is gentle, then it will roll for a shorter distance
c^2 = a^2 + b^2 c = sqrt(a^2 + b^2) = sqrt(40^2 + 81^2) = sqrt(8161) = 90 inches
18 feet
One factor is the height of the ramp. The higher the height of the ramp the further the car travels. Another factor is the surface of the ramp. With a rough surface on the ramp e.g sand paper the car travels a short distance. With a lubricated surface on the ramp e.g Vaseline the car will travel a very long distance.
true