You do not set them. If they are formed by two parallel lines and an intercept in a plane, then they are. They are even if you never even see them to set them.
No. The sum of the other two interior angles.
90
An exterior angle of a triangle is equal in measure to the sum of the other two interior angles.
any other exterior angle of the triangle * * * * * No. The sum of the two opposite interior angles.
A right angle triangle has a 90 degree angle and its other two angles add up to 90 degrees
If this for triangle then the other angle would be 32o Sum of interior angles of a triangle = 180o Therefore your question would be 180 - (112 + 36) = This would equal the other angle
If one angle of a set of alternate interior angles on parallel lines measures 77 degrees, then the other angle must also measure 77 degrees. This is because alternate interior angles are congruent when two parallel lines are cut by a transversal. Therefore, both angles are equal to each other at 77 degrees.
40 degress because a straight line is 180 degrees and an interior angle with its exterioir angle is a line spilt in half so to find the interior/exterior angle, taek 180 and subtract the interior/ exterior angle and then you will get the the other angle, sorry this is kinda conufsing!
An isosceles triangle is a triangle with two equal sides and two equal angles. The two equal sides are called the legs, and the angle between them is called the vertex angle. The two other angles in an isosceles triangle are equal and are called the base angles.
Any angle between 0 and 360 degrees. An interior angle of any polygon (other than a triangle) can have any value in that range.
Mathematically - A regular pentagon has interior angles and sides equal. Bisecting each interior angle and extending a line segment to the center gives you five equal angles (360o/5=72o). Using the triangle formed by two line segements and a side of the pentagon we know the sum of interior angles of each triangle equals (180o) and we know one angle is 72o. The sum the other two interior angles of each triangle equals (180o-72o=108o) which equals each interior angle of the pentagon (equal to the sum of these two angles). Thus the exterior angle of each corner of the pentagon equals (360o-108o=252o). :-)
In an isosceles triangle two of the sides are equal, as well as two of the angles. Because a triangle's interior angles add up to 180, only one angle could be 108, therefore the other two angle must be equal. To find the measure of the other two angles 180 - 108 = 72/2 = 36.