1 and 2 are the only common factors for 110 and 232.
These are all the divisors of 232: 1, 2, 4, 8, 29, 58, 116, 232
1, 2, 4, 8, 29, 58, 116, 232.
1, 2, 4, 8, 29, 58, 116, 232.
116
It is: 2*2*2*29 = 232
116
factor tree of 232............232............./ \.........116 2........../ \........58 2......../ \......29 2the prime factorization of 232 = 29 x 2 x 2 x 2
To find how many 2s are in a number, you need to divide it by 2. In this case we have 232, so do: 232/2 = 116. Therefore there are 116 twos in 232.
232 ÷ 2 = 116.
2 x 2 x 2 x 29 = 232
232 = 2 * 2 * 2 * 29As a product of its prime factors: 2*2*2*29 = 232