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Q: How can 1 and 2 and 3 and 4 equal 24 using each number once?

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6^(7-5) = 36

(-6)*(-5+(-7)/(-7)) = 24

(9-5)*(7-1)

96 x 1/4 = 24

The smallest value Roman numeral using each symbol only once would be MCDXLIV = 1444

78 - (6 x 9) = 78 - 54 = 24

It is: (9-4-2) times 8 = 24

-8

Try: (5-1) times (8-2) = 24

It is: (5+13)/6 times 8 = 24

It can be done by: (9-5) times 6 times 1 = 24

998,000

6 x (5 + 1 - 2) = 6 x 4 = 24

(9 - 1) x (7 - 4) = 8 x 3 = 24

943

5*6/2 + 9 = 30/2 + 9 = 15 + 9 = 24

(7+6-5) x 3 = 8 x 3 = 24

2*(6/6 + 11) = 2*(1 + 11) = 2*12 = 24. Simple!

6(5 - 7/7) = 6(5 - 1) = 6 x 4 = 24

97531

It is: 401

The closest you can get by: Using Each Number Once With Powers: 10 th the second power - 4 th the third power=46 Using each Number Once Without Powers:(4*10)-3+2 Using an indefinite amount of each number:4-*10+(3*2)-(2+2+2)

write the largest number you can make using each of the digits 7,1,0,2, and 9 just once

Using only 8's & 4's and using each atleast once...884. Using all numerals and including 8 once and 4 once...984.

[2 x (9 + 10)] - 14 = [2 x 19] - 14 = 38 - 14 = 24