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Does a hemi-sphere have a base?

Updated: 12/24/2022
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11y ago

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Yes unless told otherwise

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11y ago
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Q: Does a hemi-sphere have a base?
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Related questions

How do you calculate this a right circular cone is inscribed in a hemisphere so that base of cone coincides with base of hemisphere what is the ratio of the height of cone to radius of hemisphere?

Suppose the radius of the sphere is R. The base of the cone is the same as the base of the hemisphere so the radius of the base of the cone is also R. The apex of the cone is on the surface of the hemisphere above the centre of the base. That is, it is at the "North pole" position. So the height of the cone is also the radius of the sphere = R. So the ratio is 1.


What is half a sphere with a circular base?

Half of a sphere with a circular base is called a Hemisphere.


How Meany edges does a hemisphere have?

A hemisphere has no edges. It has one curved surface that smoothly transitions from the curved side to its base.


A 3-D figure with only one base?

How about a hemisphere ?


Which shape has one circular base?

A cone or a hemisphere or circle


Is a hemisphere a pyramid?

No. A cone could be considered the limiting case of a pyramid, but a hemisphere is not, because the lines joining the base to the apex are not straight.


What shape has one base and one curved surface?

A cone. A hemisphere.


What has 1 flat circular base an 1 curved surface?

hemisphere


What is an three dimensional figure with only one base?

A hemisphere is one example.


How many edges does a 3d hemisphere have?

It has 1 circular edge at its base


Why was the location for Pearl Harbor selected for a naval base?

pearl harbor was selected as a naval base because it had a perfect hemisphere defense zone .


How do you calculate this- a right circular cone is inscribed in a hemisphere so that base of cone coincides with base of hemisphere what is the ratio of the height of cone to radius of hemisphere?

The vertex of the cone would reach the very top of the sphere, so the height of the cone would be the same as the radius of the sphere. Therefore the ratio is 1:1, no calculation is necessary.